persamaan akar kuadrat yang akar akarnya -2 dan 3
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x² - ( x¹ + x² )x + x¹ . x² = 0
x² - ( - 2 + 3 )x + - 2 . 3 = 0
x² - 1x - 6 = 0
x² - x - 6 = 0
Jawaban:
[tex]x = - 2 \: x = 3 \\ (x + 2)(x - 3) \\ = {x}^{2} + 2x - 3x - 6 \\ = {x}^{2} - x - 6 [/tex]
[answer.2.content]
